Can you help me with this uniform motion question?

Julie and George can row at the same rate in still water. They leave Carston at the same time, Julie going upstream and George going downstream. Julie rows for two hours and arrives in Poloton, 3 miles from Carston. George rows for three hours and arrives at Burnburg, 13.5 miles from Carston. Fine the rate of the current and the rate each rows in still water.









thanks!









also if you can,provide some tips to solve uniform motion questions and combining mixture problems, because im not very good at those types of problems.Thanks!Can you help me with this uniform motion question?Start by drawing a picture.



let R be the rate of the current.

Since Julie and George row at the same rate in still water, we only need J to represent this.



1) Julie rows against the current, so her effective rate is (J-R).



Since distance = Rate * Time,

3 = (J-R)*2



2) George rows with the current, so his effective rate is (J+R).

13.5 = (J+R)*3



(1) and (2) give



J - R = 3/2

J + R = 13.5/3



sum them up



2J = 3/2 + 13.5/3

2J = 6 or

J = 3 miles per hour is their rate in still water.

Back into either equation reveals

R = 13.5/3 - J or

R = 1.5 miles per hour is the rate of the current.