A 98 kg clock initially at rest on a horizontal floor requires a 638 N horizontal force to set it in motion. A?

A 98 kg clock initially at rest on a horizontal floor requires a 638 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 517 N keeps it moving with a constant velocity.



(a) Find 渭s between the clock and the floor.



(b) Find 渭k between the clock and the floor.



A 98 kg clock initially at rest on a horizontal floor requires a 638 N horizontal force to set it in motion. A?

N = normal force = mass x g = 98kg x 10 = 980N



Coeff of static friction = F/N = 638N/980N



Coeff of kinetic friction = F/N = 517N/980N



I''ll let you do the final calculation.

A 98 kg clock initially at rest on a horizontal floor requires a 638 N horizontal force to set it in motion. A?The procedure is correct but just remember to replace the 10 with 9.8 because thats the measure of gravity

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