A 4.0kg block is on top of a 3.0kg block. The coefficient of static friction is 0.60 between the 2 blocks. The coefficient of kinetic friction between the lower block and the floor is 0.20. Force causes both blocks to cross a distance of 5.0m starting from rest. What is the least amount of time in which this motion can be completed without the top block sliding on the lower block?
Thank you in advance :)What is the least amount of time this motion could be completed?Maximum force of friction between the two blocks = 0.6 . 4 . 9.8 = 23.52 N
Maximum acceleration this force can give the 4 kg block is 23.52 /4 = 5.88 m/s/s
Time to cover 5 m with this acceleration
t = 鈭?2 . 5 / 5.88 = 1.3 s
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment