A mass of 160 g is hanging from a spring and is set into simple harmonic motion. If?

A mass of 160 g is hanging from a spring and is set into simple harmonic motion. If the period of the pendulum is 1.026 s, what is the spring constant?

If the same spring is stretched by hanging a mass of 214 g from it, how far will it stretch?A mass of 160 g is hanging from a spring and is set into simple harmonic motion. If?T=1/f=2pi sqr[M/k]

k=6000.47

;

where

T=period of time

f=frequency

M=Mass

k=constant

1.026=6.28[160/k]^0.5

0.1633=[160/k]^0.5

0.02667=160/k

k=6000

Prove;1.026=6.283*sqr[160/6000]

1.026=6.142*0.02666^.5

1.026=6.142*0.1633; Ok!



mass of 214 g from it, how far will it stretch?

k=6000,

M=214

Sorry,I don't know that formula.







A mass of 160 g is hanging from a spring and is set into simple harmonic motion. If?1st part.......



Just use the following equation



T=2蟺鈭?m/k) where...



T=time (secs)

m=mass (kg)

k=spring stiffness or constant (N/m)



Rearrange to make "k" the subject...



k=(4 pi ^ 2 * m)/T squared



Which gives...



6N/m :)



2nd part.........



Use Hooke's Law, im not as sure about this one but il give it a go...



F=-kx where...



F=force (N)

k=constant (N/m)

x=extension (m)



Rearrange...



x=F/k (ignoring negative values)



To give, 0.35m extension :)